libstdc++
std::rel_ops Namespace Reference

Functions

template<class _Tp >
bool operator!= (const _Tp &__x, const _Tp &__y)
 
template<class _Tp >
bool operator<= (const _Tp &__x, const _Tp &__y)
 
template<class _Tp >
bool operator> (const _Tp &__x, const _Tp &__y)
 
template<class _Tp >
bool operator>= (const _Tp &__x, const _Tp &__y)
 

Detailed Description

The generated relational operators are sequestered here.

Libstdc++ headers must not use the contents of rel_ops. User code should also avoid them, because unconstrained function templates are too greedy and can easily cause ambiguities.

C++20 default comparisons are a better solution.

Function Documentation

◆ operator!=()

template<class _Tp >
bool std::rel_ops::operator!= ( const _Tp &  __x,
const _Tp &  __y 
)
inline

Defines != for arbitrary types, in terms of ==.

Parameters
__xA thing.
__yAnother thing.
Returns
__x != __y

This function uses == to determine its result.

Definition at line 88 of file stl_relops.h.

◆ operator<=()

template<class _Tp >
bool std::rel_ops::operator<= ( const _Tp &  __x,
const _Tp &  __y 
)
inline

Defines <= for arbitrary types, in terms of <.

Parameters
__xA thing.
__yAnother thing.
Returns
__x <= __y

This function uses < to determine its result.

Definition at line 113 of file stl_relops.h.

◆ operator>()

template<class _Tp >
bool std::rel_ops::operator> ( const _Tp &  __x,
const _Tp &  __y 
)
inline

Defines > for arbitrary types, in terms of <.

Parameters
__xA thing.
__yAnother thing.
Returns
__x > __y

This function uses < to determine its result.

Definition at line 101 of file stl_relops.h.

◆ operator>=()

template<class _Tp >
bool std::rel_ops::operator>= ( const _Tp &  __x,
const _Tp &  __y 
)
inline

Defines >= for arbitrary types, in terms of <.

Parameters
__xA thing.
__yAnother thing.
Returns
__x >= __y

This function uses < to determine its result.

Definition at line 127 of file stl_relops.h.